A) 20%
B) 35%
C) 25%
D) 15%
Correct Answer: A
Solution :
| Force of Friction on chain = weight of hanging chain. |
| \[\mu (1-x)\rho g=x\rho g\] or \[\mu \,(l-x)=x;\] |
| \[\mu \,\ell =\,(\mu +1)x\] or \[x=\mu \ell \,(1+\mu )\]. |
| \[x=\frac{.25\ell }{.25+1}=.\frac{.25\ell }{1.25}=.2\ell \Rightarrow \,\frac{x}{\ell }=.2=20%\] |
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