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JEE Main & Advanced Physics Kinetic Theory of Gases Question Bank Topic Test - Kinetic Theory Of Gases-2

  • question_answer
    A flask is filled with 13 gm of an ideal gas at \[27{}^\circ C\]and its temperature is raised to\[52{}^\circ C\]. The mass of the gas that has to be released to maintain the temperature of the gas in the flask at \[52{}^\circ C\]and the pressure remaining the same is

    A) 2.5 g    

    B) 2.0 g

    C) 1.5 g    

    D) 1.0 g

    Correct Answer: D

    Solution :

    [d] \[PV=mrT\] Since P, V, r ® remains same
    Hence \[m\propto \frac{1}{T}\]Þ \[\frac{{{m}_{1}}}{{{m}_{2}}}=\frac{{{T}_{2}}}{{{T}_{1}}}\]Þ \[\frac{13}{{{m}_{2}}}=\frac{(273+52)}{(273+27)}=\frac{325}{300}\]
    Þ m2 = 12 gm
    i.e., mass released = 13gm - 12gm = 1gm.


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