A) \[4.16\ J/cal\]
B) \[4.18\ J/cal\]
C) \[4.20\ J/cal\]
D) \[4.22\ J/cal\]
Correct Answer: C
Solution :
| [c] We know that \[{{C}_{P}}-{{C}_{V}}=\frac{R}{J}\]Þ \[J=\frac{R}{{{C}_{P}}-{{C}_{V}}}\] |
| \[{{C}_{P}}-{{C}_{V}}=1.98\ \frac{cal}{gm-mol-K}\],\[R=8.32\frac{J}{gm-mol-K}\] |
| \[\therefore \ J=\frac{8.32}{1.98}=4.20\ J/cal\] |
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