JEE Main & Advanced Physics Kinetic Theory of Gases Question Bank Topic Test - Kinetic Theory Of Gases-2

  • question_answer
    The molecules of a given mass of a gas have a r.m.s. velocity of 200 m/sec at \[27{}^\circ C\] and \[1.0\times {{10}^{5}}\,N/{{m}^{2}}\] pressure. When the temperature is \[127{}^\circ C\]and pressure is  \[0.5\times {{10}^{5}}\,N/{{m}^{2}}\], the r.m.s. velocity in  m/sec will be

    A) \[\frac{100\sqrt{2}}{3}\]

    B) \[100\sqrt{2}\]

    C) \[\frac{400}{\sqrt{3}}\] 

    D) None of the above

    Correct Answer: C

    Solution :

    [c] r.m.s. velocity doesn't upon pressure, it depends upon temperature only i.e. \[{{v}_{rms}}\propto \sqrt{T}\]
    Þ\[\frac{{{v}_{1}}}{{{v}_{2}}}=\sqrt{\frac{{{T}_{1}}}{{{T}_{2}}}}\]Þ\[\frac{200}{{{v}_{2}}}=\sqrt{\frac{(273+27)}{(273+127)}}=\sqrt{\frac{300}{400}}\]
    Þ\[{{v}_{2}}=\frac{400}{\sqrt{3}}\,m/\sec \]
     


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