A) 7/5
B) 2/5
C) 3/2
D) 12/7
Correct Answer: C
Solution :
| [c] \[{{\gamma }_{mix}}=\frac{\frac{{{\mu }_{1}}{{\gamma }_{1}}}{{{\gamma }_{1}}-1}+\frac{{{\mu }_{2}}{{\gamma }_{2}}}{{{\gamma }_{2}}-1}}{\frac{{{\mu }_{1}}}{{{\gamma }_{1}}-1}+\frac{{{\mu }_{2}}}{{{\gamma }_{2}}-1}},\] |
| Here \[{{\mu }_{1}}={{\mu }_{2}}=1;{{\gamma }_{1}}=\frac{7}{5}\] and \[{{\gamma }_{2}}=\frac{5}{3}\] |
| \[\therefore \] \[{{\gamma }_{mix}}=\frac{3}{2}\] |
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