A) \[{{T}_{B}}-{{T}_{A}}\]
B) \[({{T}_{A}}+{{T}_{B}})/5\]
C) \[(4{{T}_{A}}+{{T}_{B}})/5\]
D) \[({{T}_{A}}-{{T}_{B}})/5\]
Correct Answer: C
Solution :
The F.B.D. of section of rope between A and B having acceleration a towards left is |
Applying Newton?s second law on section AB and section AC of rope we get |
\[{{T}_{B}}-{{T}_{A}}=Ma\] and \[{{T}_{C}}-{{T}_{A}}=\frac{M}{5}a\] |
Solving \[{{T}_{C}}=\frac{{{T}_{B}}+4{{T}_{A}}}{5}\] |
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