A) \[2U\cos \theta \]
B) \[U\cos \theta \]
C) \[2U/\cos \theta \]
D) \[U/\cos \theta \]
Correct Answer: D
Solution :
[d] |
As P and Q move down, the length \[\ell \] decreases at the rate of U m/s. |
From figure, \[{{\ell }^{2}}={{b}^{2}}+{{y}^{2}}\] |
Differentiating with respect to time? |
\[2\ell \frac{d\ell }{dt}=2y\frac{dy}{dt}\] (\[\therefore \] b is constant) |
\[\therefore \]\[\frac{dy}{dt}=\frac{\ell }{y}\cdot \frac{d\ell }{dt}=\frac{1}{\cos \theta }\cdot \frac{d\ell }{dt}=\frac{U}{\cos \theta }\] |
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