JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Topic Test - Newton's Laws Of Motion

  • question_answer
    In the arrangement shown in figure the ends P and Q of an stretchable string move downwards with a uniform speed U. Pulleys A and B are fixed. Mass M moves upwards with a speed of

    A) \[2U\cos \theta \]

    B) \[U\cos \theta \]

    C) \[2U/\cos \theta \]

    D) \[U/\cos \theta \]

    Correct Answer: D

    Solution :

    [d]
    As P and Q move down, the length \[\ell \] decreases at the rate of U m/s.
    From figure, \[{{\ell }^{2}}={{b}^{2}}+{{y}^{2}}\]
    Differentiating with respect to time?
    \[2\ell \frac{d\ell }{dt}=2y\frac{dy}{dt}\] (\[\therefore \] b is constant)
    \[\therefore \]\[\frac{dy}{dt}=\frac{\ell }{y}\cdot \frac{d\ell }{dt}=\frac{1}{\cos \theta }\cdot \frac{d\ell }{dt}=\frac{U}{\cos \theta }\]


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