| Two masses\[{{\text{m}}_{1}}\]and\[{{\text{m}}_{\text{2}}}\]are attached to the ends of a massless string which passes over a frictionless pulley attached to the top of an inclined plane. The angle of inclination of the plane is \[\theta \]. Take \[g=10m{{s}^{-2}}\] |
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| If \[{{m}_{1}}=10\,kg,\,\,{{m}_{2}}=5\,kg,\] \[\theta ={{30}^{o}},\] what is the acceleration of mass \[{{m}_{2}}\]? |
A) zero
B) \[(2/3)\text{ }m{{s}^{-2}}\]
C) \[5\text{ }m{{s}^{-2}}\]
D) \[10/3\text{ }m{{s}^{-2}}\]
Correct Answer: A
Solution :
[a] \[a=\frac{({{m}_{2}}-{{m}_{1}}\sin \alpha )g}{({{m}_{1}}+{{m}_{2}})}=\frac{(5-10\sin {{30}^{{}^\circ }})g}{({{m}_{1}}+{{m}_{2}})}=0\]
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