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JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Topic Test - Nuclear Physics and Radioactivity

  • question_answer
    In the given nuclear reaction A, B, C, D, E represents \[_{92}{{U}^{238}}{{\xrightarrow{\alpha }}_{B}}T{{h}^{A}}{{\xrightarrow{\beta }}_{D}}P{{a}^{C}}{{\xrightarrow{E}}_{92}}{{U}^{234}}\]

    A) A = 234, B = 90, C = 234, D = 91, E = \[\beta \]

    B) A = 234, B = 90, C = 238, D = 94, E = \[\alpha \]

    C) A = 238, B = 93, C = 234, D = 91, E = \[\beta \]

    D) A = 234, B = 90, C = 234, D = 93, E = \[\alpha \]

    Correct Answer: A

    Solution :

    [a] \[_{92}{{U}^{238}}\xrightarrow{\alpha }{{\,}_{90}}T{{h}^{234}}\,\xrightarrow{\beta }{{\,}_{91}}P{{a}^{234}}\]    \[\xrightarrow{E{{(}_{-1}}{{\beta }^{o}})}{{\,}_{92}}{{U}^{234}}\]


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