A) 1.6
B) 6
C) 2
D) 1.2
Correct Answer: A
Solution :
[a] \[K.E.=h\nu -h{{\nu }_{0}}\]\[=8\ eV-\left( \frac{6\times {{10}^{-34}}\times 1.6\times {{10}^{15}}}{1.6\times {{10}^{-19}}}eV \right)\] = \[8\ eV-6\ eV=2\ eV\]
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