JEE Main & Advanced Physics Photo Electric Effect, X- Rays & Matter Waves Question Bank Topic Test - Photo Electric Effect, X-Rays & Matter Waves

  • question_answer
    The de-Broglie wavelength \[\lambda \] associated with an electron having kinetic energy E is given by the expression

    A) \[\frac{h}{\sqrt{2mE}}\]

    B) \[\frac{2h}{mE}\]

    C) \[2mhE\]

    D) \[\frac{2\sqrt{2mE}}{h}\]

    Correct Answer: A

    Solution :

    [a] \[\frac{1}{2}m{{v}^{2}}=E\Rightarrow mv=\sqrt{2mE};\ \ \therefore \ \ \lambda =\frac{h}{mv}=\frac{h}{\sqrt{2mE}}\]

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