JEE Main & Advanced Physics Photo Electric Effect, X- Rays & Matter Waves Question Bank Topic Test - Photo Electric Effect, X-Rays & Matter Waves

  • question_answer
    The kinetic energy of electron and proton is \[{{10}^{-32}}J\]. Then the relation between their de-Broglie wavelengths is

    A) \[{{\lambda }_{p}}<{{\lambda }_{e}}\]

    B) \[{{\lambda }_{p}}>{{\lambda }_{e}}\]

    C) \[{{\lambda }_{p}}={{\lambda }_{e}}\]

    D) \[{{\lambda }_{p}}=2{{\lambda }_{e}}\]

    Correct Answer: A

    Solution :

    [a] By using \[\lambda =\frac{h}{\sqrt{2mE}}\]   
    \[E={{10}^{-32}}J=\text{Constante}\]for both particles.
    Hence \[\lambda \propto \frac{1}{\sqrt{m}}\]
    Since \[{{m}_{p}}>{{m}_{e}}\] so \[{{\lambda }_{p}}<{{\lambda }_{e}}.\]

You need to login to perform this action.
You will be redirected in 3 sec spinner