• # question_answer The approximate wavelength of  a photon of energy 2.48 eV is                                 A) 500 $\overset{\text{o}}{\mathop{\text{A}}}\,$ B) 5000 $\overset{\text{o}}{\mathop{\text{A}}}\,$ C) 2000 $\overset{\text{o}}{\mathop{\text{A}}}\,$ D) 1000 $\overset{\text{o}}{\mathop{\text{A}}}\,$

Correct Answer: B

Solution :

[b] By using  $E(eV)=\frac{12375}{\lambda (\overset{\text{o}}{\mathop{\text{A}}}\,)}$ $\Rightarrow \,\,\lambda \,=\frac{12375}{2.48}=4989.9\,\overset{\text{o}}{\mathop{\text{A}}}\,\,\approx \,5000\,\overset{\text{o}}{\mathop{\text{A}}}\,$

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