A) 6
B) 1
C) 4
D) 2
Correct Answer: C
Solution :
[c] \[\because \] 100gm Hb contain = 0.33gm Fe |
\[\therefore \] 67200gm Hb = \[\frac{67200\times 0.33}{100}gm\ Fe\] |
gm atom of Fe =\[\frac{672\times 0.33}{56}=4\]. |
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