A) 21
B) 27
C) 38
D) 49
Correct Answer: D
Solution :
The equivalent weight of |
\[{{H}_{3}}P{{O}_{4}}=\frac{\text{molecular weight}}{2}\] |
\[\because \] mole wt of \[{{H}_{3}}P{{O}_{4}}\]= 3 + 31 + 64 = 98 |
\ \[\frac{98}{2}=49\] |
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