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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Topic Test - Thermodynamical Process (2021)

  • question_answer
    One gm mol of a diatomic gas \[(\gamma =1.4)\] is compressed adiabatically so that its temperature rises from \[{{27}^{o}}C\] to \[{{127}^{o}}C\]. The work done will be

    A) 2077.5 joules     

    B) 207.5 joules

    C) 207.5 ergs

    D) None of the above

    Correct Answer: A

    Solution :

    [a] \[W=\frac{R}{\gamma -1}({{T}_{1}}-{{T}_{2}})\]      \[=\frac{8.31\times \{(273+27)-(273+127)\}}{1.4-1}=-2077.5\ joules\]


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