• # question_answer An ideal gas heat engine operates in Carnot cycle between 227°C and 127°C. It absorbs $6\times {{10}^{4}}$ cals of heat at higher temperature. Amount of heat converted to work is A) $2.4\times {{10}^{4}}$cal B) $6\times {{10}^{4}}$ cal C) $1.2\times {{10}^{4}}$ cal D) $4.8\times {{10}^{4}}$ cal

 [c] $\eta =\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}=\frac{W}{Q}$Þ $W=\frac{Q({{T}_{1}}-{{T}_{2}})}{{{T}_{1}}}$ $=\frac{6\times {{10}^{4}}\left[ (227+273)-(273+127) \right]}{(227+273)}$ $=\frac{6\times {{10}^{4}}\times 100}{500}$$=1.2\times {{10}^{4}}cal$