A) \[1\times {{10}^{5}}\ N/{{m}^{2}}\]
B) \[1\times {{10}^{-8}}\ N/m2\]
C) \[1.4\ N/{{m}^{2}}\]
D) \[1.4\times {{10}^{5}}N/{{m}^{2}}\]
Correct Answer: D
Solution :
[d]\[{{E}_{\varphi }}=\gamma P=1.4\times (1\times {{10}^{5}})=1.4\times {{10}^{5}}N/{{m}^{2}}\]
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