• # question_answer One mole of ${{O}_{2}}$ gas having a volume equal to 22.4 litres at ${{0}^{o}}C$ and 1 atmospheric pressure in compressed isothermally so that its volume reduces to 11.2 litres. The work done in this process is A) $1672.5\ J$ B) 1728 J C) $-1728J$ D) $-1572.5\ J$

 [d]$W=-\mu RT{{\log }_{e}}\frac{{{V}_{2}}}{{{V}_{1}}}=-1\times 8.31\times (273+0){{\log }_{e}}\left( \frac{22.4}{11.2} \right)$ $=-\,8.31\times 273\times {{\log }_{e}}2$$=-1572.5J$ [$\because$${{\log }_{e}}2=0.693$]