A) 450 K
B) 375 K
C) 225 K
D) 405 K
Correct Answer: B
Solution :
| [b] \[\frac{{{T}_{2}}}{{{T}_{1}}}={{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{\gamma -1}}\Rightarrow {{T}_{2}}=300\,{{\left( \frac{27}{8} \right)}^{\frac{5}{3}-1}}=300\,{{\left( \frac{27}{8} \right)}^{\frac{2}{3}}}\] |
| \[=300\,{{\left\{ {{\left( \frac{27}{8} \right)}^{1/3}} \right\}}^{2}}=800\,{{\left( \frac{3}{2} \right)}^{2}}=675K\] |
| \[\Rightarrow \ \Delta T=675-300=375\ K\] |
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