A) \[25{}^\circ C\]
B) \[40{}^\circ C~\]
C) \[15{}^\circ C\]
D) \[{{12.5}^{o}}C\]
Correct Answer: A
Solution :
\[t=\frac{\left( {{P}_{1}}-{{P}_{0}} \right)}{\left( {{P}_{100}}-{{P}_{0}} \right)}\times 100{}^\circ C\] |
\[=\frac{\left( 60-50 \right)}{\left( 90-50 \right)}\times 100=25{}^\circ C\] |
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