JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Topic Test - Thermometry, Calorimetry & Thermal Expansion

  • question_answer
    Steam at \[1\,\,\text{atm}\,\,and\,\,100{}^\circ C\] enters a radiator & leaves as water at \[1\,\,\text{atm}\,\,and\,\,80{}^\circ C,\] take \[{{L}_{y}}=540\text{ cal/cm}\] and \[{{s}_{water}}=11\text{ }cal/gm/{}^\circ C.\] If the total energy given off as heat, the % age arises from the cooling of water is

    A) 100                              

    B) 54      

    C) 3.6       

    D) 8.2

    Correct Answer: C

    Solution :

    Let m is the amount of steam that passes off the radiator.
    Heat released due to condensation of steam, \[{{H}_{1}}=m{{L}_{v}}=540\,\,m\,cal\]
    Heat released due to cooling of water,
    \[{{H}_{2}}=ms\Delta \theta =m\times 1\times 20=20m\,cal\]
    Required percentage
    \[=\frac{{{H}_{2}}}{{{H}_{1}}+{{H}_{2}}}\times 100=\frac{20m}{560m}\times 100=3.6%\]


You need to login to perform this action.
You will be redirected in 3 sec spinner