A) 18gm
B) 20gm
C) 22gm
D) 24gm
Correct Answer: C
Solution :
Heat released by steam inconversion to water at \[100{}^\circ C\] is \[{{Q}_{1}}=\text{ }mL\text{ }=\text{ }4\text{ }x\text{ }540\text{ }=\text{ }2160\text{ }cal.\]Heat required to raise temperature of water from is\[{{Q}_{2}}=\text{mS}\Delta \text{ }\!\!\theta\!\!\text{ =20}\times \text{1}\times \text{54=1080J}\]\[{{Q}_{1}}>{{Q}_{2}}\,\text{and}\,\frac{{{Q}_{1}}}{{{Q}_{2}}}=2\]Hence all steam is not converted to water only half steam shall be converted to water\[\therefore \] Final mass of water \[=20\text{ }+\text{ }2\text{ }=22\text{ }gm\]You need to login to perform this action.
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