A) 0.5 cm
B) 1.0 cm
C) 1.5 cm
D) 2.0 cm
Correct Answer: B
Solution :
Increase in length\[\Delta L={{L}_{0}}\,\alpha \,\Delta \theta \]\[=10\times 10\times {{10}^{-6}}\times (100-0)={{10}^{-2}}m=1\,cm\]You need to login to perform this action.
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