A) 1 : 2
B) 1 : 8
C) 1 : 4
D) 2 : 1
Correct Answer: B
Solution :
| Thermal capacity = Mass \[\times \] Specific heat |
| Due to same material both spheres will have same specific heat. Also mass = Volume (V) \[\times \] Density (\[\rho \]) |
| \ Ratio of thermal capacity |
| \[=\frac{{{m}_{1}}}{{{m}_{2}}}=\frac{{{V}_{1}}\rho }{{{V}_{2}}\rho }=\frac{\frac{4}{3}\pi r_{1}^{3}}{\frac{4}{3}\pi r_{2}^{3}}={{\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{3}}={{\left( \frac{1}{2} \right)}^{3}}=1:8\] |
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