question_answer

A pendulum clock keeps correct time at \[0{}^\circ C\]. Its mean coefficient of linear expansions is \[\alpha /{}^\circ C\], then the loss in seconds per day by the clock if the temperature rises by \[t{}^\circ C\] is               

A) \[\frac{\frac{1}{2}\alpha \,t\times 864000}{1-\frac{\alpha \,t}{2}}\]

B) \[\frac{1}{2}\alpha \,t\times \,86400\]

C) \[\frac{\frac{1}{2}\alpha \,t\times 86400}{{{\left( 1-\,\frac{\alpha \,t}{2} \right)}^{2}}}\]  

D) \[\frac{\frac{1}{2}\alpha \,t\times 86400}{1+\frac{\alpha \,t}{2}}\]