A) \[\frac{E}{16}\]
B) \[\frac{E}{4}\]
C) \[4E\]
D) \[16E\]
Correct Answer: A
Solution :
\[E\propto {{T}^{4}}\Rightarrow \frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{T}^{4}}}{{{T}^{4}}}\times {{2}^{4}}\Rightarrow {{E}_{2}}=\frac{E}{16}\]
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