A) 2.99 W
B) 1.89 W
C) 1.18 W
D) 0.99 W
Correct Answer: D
Solution :
Loss of heat \[\Delta Q=A\varepsilon \sigma ({{T}^{4}}-T_{0}^{4})t\] \[\Rightarrow \] Rate of loss of heat \[\frac{\Delta Q}{t}=A\varepsilon \sigma ({{T}^{4}}-T_{0}^{4})\] \[=10\times {{10}^{-4}}\times 1\times 5.67\times {{10}^{-8}}{{\{273+127)}^{4}}-{{(273+27)}^{4}}\}\] = 0.99 W.
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