A) Specific heat of the body
B) Mass of the body
C) Nature of the surface of the body
D) All of these
Correct Answer: D
Solution :
[d] \[-ms\frac{dT}{dt}=4Ae\sigma \Delta T\times {{T}^{3}}\] \[\Rightarrow \frac{dT}{dt}=-\frac{\sigma eA\times 4{{J}^{3}}\Delta T}{ms}\]
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