A) \[1.2\times {{10}^{-3}}{{\,}^{o}}C\]
B) \[2.4\times {{10}^{-3}}{{\,}^{o}}C\]
C) \[3.6\times {{10}^{-3}}{{\,}^{o}}C\]
D) \[4.8\times {{10}^{-3}}{{\,}^{o}}C\]
Correct Answer: A
Solution :
[a] Mass of steam produced, \[\frac{dm}{dt}=\frac{1}{60}g/s\]. Hence heat transferred per sec to water \[\frac{\Delta Q}{\Delta t}={{L}_{v}}\frac{dm}{dt}=\frac{KA\theta }{d}\] where \[\theta \] is the required temperature difference \[\Rightarrow \]\[\theta =\frac{540\times \frac{1}{60}\times 0.2\times {{10}^{-3}}}{0.5\times 3000}=1.2\times {{10}^{-3}}{{\,}^{0}}C\]
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