question_answer

At the height 80 m, an aeroplane is moving with 150 m/s. A bomb is dropped from it so as to hit a target. At what distance from the target should the bomb be dropped (given \[g=\text{ }10m/{{s}^{2}}\])           

A) 605.3 m

B) 600 m

C) 80 m    

D) 230 m

Correct Answer: A

Solution :

[a] The horizontal distance covered by bomb,             \[BC={{v}_{H}}\times \sqrt{\frac{2h}{g}}=150\sqrt{\frac{2\times 80}{10}}=660m\] \ The distance of target from dropping point of bomb, \[AC=\sqrt{A{{B}^{2}}+B{{C}^{2}}}=\sqrt{{{(80)}^{2}}+{{(600)}^{2}}}=605.3\,m\]