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JEE Main & Advanced Physics Two Dimensional Motion Question Bank Topic Test - Two Dimensional Motion

  • question_answer
    Galileo writes that for angles of projection of a projectile at angles \[(45+\theta )\] and \[(45-\theta )\], the horizontal ranges described by the projectile are in the ratio of (if \[\theta \le 45)\] 

    A) 2 : 1     

    B) 1 : 2

    C) 1 : 1

    D) 2 : 3

    Correct Answer: C

    Solution :

    [c] For angle\[(45{}^\circ -\theta )\], \[R=\frac{{{u}^{2}}\sin (90{}^\circ -2\theta )}{g}=\frac{{{u}^{2}}\cos 2\theta }{g}\] For angle\[(45{}^\circ +\theta )\], \[R=\frac{{{u}^{2}}\sin (90{}^\circ +2\theta )}{g}=\frac{{{u}^{2}}\cos 2\theta }{g}\]


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