A) \[P=W\tan \theta \]
B) \[\vec{T}+\vec{P}+\vec{W}=0\]
C) \[{{T}^{2}}={{P}^{2}}+{{W}^{2}}\]
D) \[T=P+W\]
Correct Answer: C
Solution :
[c] | |
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As the metal sphere is in equilibrium under the effect of the three forces therefore | |
\[\overrightarrow{T}+\overrightarrow{P}+\overrightarrow{W}=0\] | |
From the figure | |
\[T\,\cos \theta =W\] | ...(i) |
\[T\,\sin \theta =P\] | ...(ii) |
From equation (i) and (ii) we get | |
\[P=W\,\tan \theta \] and \[{{T}^{2}}={{P}^{2}}+{{W}^{2}}\] |
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