question_answer

A particle moves along a path ABCD as shown in the figure. Then the magnitude of net displacement of the particle from position A to D is:

A) 10 m

B) \[5\sqrt{2}\,m\]

C) 9 m

D) \[7\sqrt{2}\,m\]

Correct Answer: D

Solution :

[d] As seen from the figure the displacement is \[\sqrt{{{(AF)}^{2}}+{{(FD)}^{2}}}=7\sqrt{2}\,m\].