NEET Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Topic Test - Work Energy Power

  • question_answer
    A simple pendulum with a bob of mass 'm' oscillates from A to C and back to A such that PB is H. If the acceleration due to gravity is 'g', then the velocity of the bob as it passes through B is      

    A) zero

    B) \[2\,gH\]

    C) \[mgH\]

    D) \[\sqrt{2gH}\]

    Correct Answer: D

    Solution :

    [d] At B, the velocity is maximum. Taking vertical downward motion of body from A to B, we have, \[u=0,\,\,a=g,\,\,s=H\] and \[v=?\]
    \[{{v}^{2}}={{u}^{2}}+2\,as;\] or \[{{v}^{2}}=0+2gH\] or \[v=\sqrt{2g\,H}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner