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JEE Main & Advanced Physics Ray Optics Question Bank Total Internal Reflection

  • question_answer
    With respect to air critical angle in a medium for light of red colour \[[{{\lambda }_{1}}]\] is q. Other facts remaining same, critical angle for light of yellow colour \[[{{\lambda }_{2}}\]]  will be          [MP PET 1999]

    A)            \[\theta \]                             

    B)            More than \[\theta \]

    C)            Less than \[\theta \]         

    D)            \[\frac{\theta {{\lambda }_{1}}}{{{\lambda }_{2}}}\]

    Correct Answer: C

    Solution :

                       Critical angle = \[{{\sin }^{-1}}\left( \frac{1}{\mu } \right)\]                    \\[\theta ={{\sin }^{-1}}\left( \frac{1}{{{\mu }_{{{\lambda }_{1}}}}} \right)\] and \[\theta '={{\sin }^{-1}}\left( \frac{1}{{{\mu }_{{{\lambda }_{2}}}}} \right)\]            Since \[{{\mu }_{{{\lambda }_{2}}}}>{{\mu }_{{{\lambda }_{1}}}}\], hence \[\theta '<\theta \]


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