A) \[v(1-\cos \theta )\]
B) \[v/\sin \theta \]
C) \[v/\cos \theta \]
D) \[v(1-\sin \theta )\]
Correct Answer: B
Solution :
\[_{2}{{\mu }_{1}}=\frac{1}{\sin \theta }\]\[\Rightarrow \frac{{{\mu }_{1}}}{{{\mu }_{2}}}=\frac{1}{\sin \theta }\]\[\Rightarrow \frac{{{v}_{2}}}{{{v}_{1}}}=\frac{1}{\sin \theta }\]\[\Rightarrow \frac{{{v}_{2}}}{v}=\frac{1}{\sin \theta }\] \[\Rightarrow {{v}_{2}}=\frac{v}{\sin \theta }\]
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