A) \[55{}^\circ \]
B) \[65{}^\circ \]
C) \[40{}^\circ \]
D) \[45{}^\circ \]
Correct Answer: D
Solution :
(d): We know. \[{{x}^{2}}+{{y}^{2}}={{z}^{2}}\] then \[{{x}^{2}}+{{y}^{2}}=2xy\] \[\Rightarrow \] \[{{(x-y)}^{2}}=0\]\[\Rightarrow \]\[x=y\] \[\Rightarrow \]isosceles right \[\Delta ;\]\[\Rightarrow \]\[\text{ }\theta =45{}^\circ \]
You need to login to perform this action.
You will be redirected in
3 sec
