A) S.A.S. property
B) S.S.S. property
C) R.H.S. property
D) A.S.A. property
Correct Answer: D
Solution :
In\[\Delta ABD\]and \[\Delta ADC,\angle B=\angle C\](Given) \[\Rightarrow \]\[AB=BC\] \[\angle ADB=\angle ADC\]and\[BD=DC\] (Since, \[AD\bot BC.\]) \[\therefore \]\[\Delta ADB\cong \Delta ADC\](By A.S.A property)You need to login to perform this action.
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