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10th Class Mathematics Triangles Question Bank Triangles

  • question_answer
    In the given figure, \[\angle RPS=\angle RQP=90{}^\circ ,\]\[PQ=1,PS=2;QR=3;\] and right \[\angle s\]as shown. Measurement of \[PR+RS=\]________

    A)  \[\sqrt{12}-\sqrt{10}\]               

    B)  \[\sqrt{17}+\sqrt{13}\]

    C)  \[\sqrt{2}\left( \sqrt{5}+\sqrt{7} \right)\]

    D)  \[\sqrt{10}+\sqrt[7]{2}\]

    Correct Answer: C

    Solution :

    (c): \[PR=\sqrt{{{1}^{2}}+{{3}^{2}}}=\sqrt{10};RS=\sqrt{{{\left( \sqrt{10} \right)}^{2}}+{{2}^{2}}}=\sqrt{14}\]           


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