A) \[{{72}^{o}}\]
B) \[{{36}^{o}}\]
C) \[{{144}^{o}}\]
D) \[{{108}^{o}}\]
Correct Answer: A
Solution :
Since \[PQ=PR,\] \[\angle Q=\angle R\] Given that \[\angle Q=2\,\,\angle P,\] we have \[\angle P+\angle Q+\angle R={{180}^{o}}\] \[\Rightarrow \] \[\frac{\angle Q}{2}+\angle Q+\angle Q={{180}^{o}}\] \[\Rightarrow \] \[\frac{5}{2}\,\,\angle Q={{180}^{o}}\,\,\Rightarrow \,\,\angle Q={{72}^{o}}\]You need to login to perform this action.
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