question_answer

The angle of elevation of a tower from a distance 50 m from its foot is \[30{}^\circ \]. The height of the tower is

A) \[50\sqrt{3\,m}\]

B) \[50\sqrt{3\,m}\]

C) \[75\sqrt{3}\,m\]

D) \[\frac{75}{\sqrt{3}}\,m\]

Correct Answer: B

Solution :

[b] Let height of the tower be h m. Then, \[\tan 30{}^\circ =\frac{h}{50}\] \[\Rightarrow \]\[h=50\frac{1}{\sqrt{3}}=\frac{50}{\sqrt{3}}\,m\]