A) \[\frac{(sinA+sinB)}{(sinA-sinB)}=\frac{\tan \frac{A+B}{2}}{\tan \frac{A-B}{2}}\]
B) \[{{\sin }^{2}}A-{{\cos }^{2}}B=\sin (A+B)sin(A-B)\]
C) \[cosA-\cos B=2\cos \frac{A+B}{2}coss\frac{B-A}{2}\]
D) \[co{{s}^{2}}A-{{\cos }^{2}}B=\sin (A+B)sin(B-A)\]
Correct Answer: C
Solution :
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