A) \[4\cos \theta \,\cos 2\theta \]
B) \[4\sin \theta \,\cos 2\theta \]
C) \[4\sin \theta \,\sin 2\theta \]
D) \[4\cos \theta \,\sin 2\theta \]
Correct Answer: B
Solution :
\[\frac{\sin \,4\theta }{\cos \,\theta }=\frac{2\,\sin \,2\theta \,\cos \,2\theta }{\cos \theta }\] \[=\frac{4.\,\sin \theta \,\cos \theta .\cos 2\theta }{\cos \theta }\] \[=4\,\sin \theta \,\cos \,2\theta \]
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