A) \[\frac{10}{\sqrt{3}}m\]
B) \[10\sqrt{3}m\]
C) \[\frac{20}{\sqrt{3}}m\]
D) 30 m
Correct Answer: D
Solution :
(d) \[tan{{30}^{{}^\circ }}=\frac{10}{PQ}\] \[\frac{1}{\sqrt{3}}=\frac{10}{PQ},PQ=10\sqrt{3}\] \[\tan {{60}^{{}^\circ }}=\frac{SQ}{10\sqrt{3}}=\frac{SR+10}{10\sqrt{3}}\] \[\sqrt{3}=\frac{SR+10}{10\sqrt{3}}\] SR = 20 \[SQ=20+10=30\]
You need to login to perform this action.
You will be redirected in
3 sec
