A) \[\frac{p}{q}\]
B)
C) pq
D) \[{{P}^{2}}{{V}^{2}}\]
Correct Answer: B
Solution :
(b) \[AB=\sqrt{\left( \sqrt{{{p}^{2}}+{{q}^{2}}} \right)-{{p}^{2}}}\] \[={{p}^{2}}+{{q}^{2}}-{{p}^{2}}=\sqrt{{{q}^{2}}}=q\] \[tan\theta =\frac{q}{p}\]
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