Railways NTPC (Technical Ability) Turbomachinery Question Bank Turbomachinery

  • question_answer
    The isentropic enthalpy drop in moving blade is two - thirds of the isentropic enthalpy drop in fixed blades of a turbine. The degree of reaction will be:    

    A) 0.4                               

    B) 0.6              

    C) 0.66                             

    D) 1.66           

    Correct Answer: A

    Solution :

    \[{{R}_{d}}=\frac{{{(\Delta h)}_{m}}}{{{(\Delta h)}_{m}}{{(\Delta h)}_{f}}}=\frac{\frac{2}{3}{{(\Delta h)}_{f}}}{\frac{2}{3}{{(\Delta h)}_{f}}+{{(\Delta h)}_{f}}}\] \[=\frac{\frac{2}{3}}{\frac{2}{3}+1}=\frac{2}{5}=0.4\]


You need to login to perform this action.
You will be redirected in 3 sec spinner