A) 295.2 kW
B) 237.0 kW
C) 271.0 kW
D) 265.2 kW
Correct Answer: C
Solution :
\[p=\gamma \,\,QH\,\,\,{{\eta }_{0}}=\frac{9.81\times 1000\times 30\times 10\times 0.92}{{{10}^{3}}}\]\[=270.76=271\,\,kW\]You need to login to perform this action.
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