A) Chloretone
B) Chloroquin
C) Chloropicrin
D) Chloropropyl chloride
Correct Answer: A
Solution :
\[\begin{matrix} C{{H}_{3}} \\ C{{H}_{3}} \\ \end{matrix}>C=0+CHC{{l}_{3}}\to \underset{\text{Chloretone}}{\mathop{\begin{matrix} C{{H}_{3}} \\ C{{H}_{3}} \\ \end{matrix}>C<\begin{matrix} OH\,\, \\ CC{{l}_{3}} \\ \end{matrix}}}\,\]You need to login to perform this action.
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