• # question_answer A simple spring mass vibrating system has a natural frequency of N. If the spring, stiffness is halved and the mass is doubled, then the natural frequency will become: A) N/2                              B) 2NC) 4N                               D) 8N

$\,\,{{\omega }_{n1}}=\sqrt{\frac{k}{m}},$ $\omega \,{{n}_{2}}=\sqrt{\frac{k}{2}\times \frac{1}{2m}}=\frac{1}{2}\sqrt{\frac{k}{m}}=\frac{1}{2}{{\omega }_{n1}}=\frac{N}{2}$