A) N/2
B) 2N
C) 4N
D) 8N
Correct Answer: A
Solution :
\[\,\,{{\omega }_{n1}}=\sqrt{\frac{k}{m}},\] \[\omega \,{{n}_{2}}=\sqrt{\frac{k}{2}\times \frac{1}{2m}}=\frac{1}{2}\sqrt{\frac{k}{m}}=\frac{1}{2}{{\omega }_{n1}}=\frac{N}{2}\]
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